if i have View*Projection is there anyway to get View and Projection back from it?
Only if you had the inverse of one of the matrices, otherwise they are stuck together.
Yes, invert the matrix, then IIRC you can extract the view axes and position as follows:.
XAxis = Homogenize(Point(1, 0, 0, 1) * InverseViewProjection) - Homogenize(Point(0, 0, 0, 1) * InverseViewProjection)
YAxis = Homogenize(Point(0, 1, 0, 1) * InverseViewProjection) - Homogenize(Point(0, 0, 0, 1) * InverseViewProjection)
ZAxis = Homogenize(Point(0, 0, 1, 1) * InverseViewProjection) - Homogenize(Point(0, 0, 0, 1) * InverseViewProjection)
CameraPos = Homogenize(Point(0, 0, -1, 0) * InverseViewProjection)
Here "Homogenize" means convert from a 4D point back to a 3D one by dividing by w. These equations may be able to be simplified a bit; I'm not sure. Also be wary of the LHS/RHS conversion, there may be a sign change needed someplace with respect to the Z axis. Anyway, once you have the camera position and axes you can easily reconstruct the view matrix, then Inverse(View) * ViewProjection gets you the projection.
That looks very complicated , would you be able to make a sample in D3D format etc
No, I don't use D3D. Come on, I gave you the exact equations, just code it up.
Thats amazing! I never would have thought that was possible, im a lamer.
Oh come on Reedbeta, what kind of staff member you think you are that you don't code stuff for people in their preferred environment and language, huh?!
Heheh, I know, I'm pretty useless.